Answers

2014-06-04T15:55:15+05:30
Let W Kg. obtained CO2
CaCO3  +  2HCl   -----------------------> CaCl2 + CO2 + H2O
number of mole CaCO3 = number of mole of CO2
number of mole = weight / molecular weight 
10*1000/100 = W/44         (molecular weight of CaCO3 = 100 & CO2 = 44)
W = 4000 gm.
W = 4.4 Kg.
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