# Five years ago a man was seven times as old as his son. Five years hence, the father will be 3 times as old as his son. Find their present ages.

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by kekureddy

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by kekureddy

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Therefore, the age of the man = 7x

The present age of the son = x+5

The present age of the man = 7x+5

The age of the son after 5 years = x+5+5=x+10

The age of father after 5 years = 7x+5+5=7x+10

According to the question

7x+10=3(x+10)

7x+10=3x+30

7x-3x=30-10

4x=20

x=20÷4=5

Therefore, the present age of

the son=x+5=5+5=10 years

father=7x+5=7×5+5=40 years