# Five years ago a man was seven times as old as his son. Five years hence, the father will be 3 times as old as his son. Find their present ages.

1
by kekureddy

Log in to add a comment

by kekureddy

Log in to add a comment

Let Present age of father be

and present age of Son be

Five years Ago ,

Father's age = x-5

Son's age = y - 5

According to Question ,

x - 5 = 7 (y -5 )

or x -5 = 7y - 35

or x =7y - 35 + 5

or

Five Years Hence ,

Father's age = x+5

Son's age = y+5

According to question ,

x+5 = 3(y+5)

x+5 = 3y + 15

or x = 3y +15 - 5

or

From ist and 2nd we get

7y - 30 =3y + 10

or 7y - 3y = 10 +30

or 4y = 40

or

hence Present age of Son = 10 years

x = 7*10 - 30

or x= 70 - 30

or x= 40

Therefore Present age of Father = 40 years

Hope this helps you!!

Thank You!!