Answers

2015-07-25T20:32:14+05:30
Let time taken by man = time taken by bus =x
for bus:
u=0
a=1m/s²
t=x
S=ut+1/2at²  =o×x +1/2×1×x²  =x²/2
for man :
v=10m/s
t=x
S=v×t = 10x
distance travelled by man - distance travelled by bus =48
so, 10x-x²/2 =48
20x-x²/2=48
20x-x²=48×2
         =96
20x -x²-96 =0
x²-20x+96=0
x²-12x-8x+96=0
x(x-8)-12(x-8)=0
(x-12)(x-8)=0
x=12 or x=8
minimum time = 8sec

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