Answers

2015-07-25T20:56:29+05:30
Sinx+cosx=3^(1/2)
tanx+cotx=sinx/cosx + cosx/sinx = (sinx)^2 + (cosx)^2 / sinxcosx= 1/sinxcosx
now, squaring  the first equation, we have,
sinx^2+cosx^2+2sinxcosx=3
1+2sinxcosx=3
so, sinxcosx=1
putting it in the second equation,
tanxcotx= 1/sinxcosx=1
hence proved.
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