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## Answers

The Brainliest Answer!

You can solve this by simply remember (n+l) formula

for

orbital Value of l

s 0

p 1

d 2

f 3

and n is the coefficient in term i.e. 2s have n=2 and l=0

for s n+l starts from 1

for p it starts from 3

for d it is 5

and for f it is 7

So if the value of (n+l) is in the range given above then it is valid orbital