Answers

2014-06-05T11:53:53+05:30
Suppose   a^x=N
than taking log on both side
loga^x=logN
xloga=logN
x=logN/loga
x=logN to base a
similarly there are different formula of log
log(mn)=logm+logn
log(m/n)=logm=logn
logm^n=nlogm
logm to base n =(logm)/(logn)
d/dxlogx=1/x
lim x=0 log[(1-x)/x] =-1

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