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2015-07-30T22:39:16+05:30

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Let us resolve the components of forces along the positive x axis = East... and  positive y axis ie., North..

   F_x = 20 Cos 30⁰  - 30 Cos 45⁰ - 35 Cos 40⁰  Newtons
         =  - 30.704 Newtons in the direction of  West...

  F_y =  25 + 30 Cos (90-45)  - 35 Cos (90-40)
          = 23.715  Newtons  towards  North.

Resultant is =  [tex]\sqrt{F_x^2+F_y^2}=  38.796  Newtons
direction is :  Ф deg. North of West
     Tan Ф =  | F_y /  F_x | =  23.715 / 30.704 = 37.68 deg.

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