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2015-08-04T01:00:01+05:30

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Potential energy of the system = 1/(4πε) * Q1 Q2 / d
     where ε = electrostatic permittivity
               Q1 = charge = 12 μC
               Q2 = 10 μC          d = 10 cm  = 0.1 meter

       U1 = 9 * 10⁹ * 12 * 10⁻⁶ * 10 * 10⁻⁶ / 0.10
             = 10.8 Joules

       d2 = 6 cm
         U2 = 9 * 10⁹ * 12 * 10⁻⁶ * 10 * 10⁻⁶ / 0.06
                 = 18 Joules 

  The work done by the external force agent in bringing together the charges from 10 cm to 6 cm is  18 - 10.8 J = 7.2 Joules

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