# Give the temperature on Fahrenheit scale which is numerically equal to and opposite of in Celsius scale.Show Full Procedure.

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by AcharyaVII

PLease answer quick

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by AcharyaVII

PLease answer quick

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°F = (9*°C/5) + 32

a/q,

°F = -°C

now,

°C = -9*°C/5 + 32

°C+9*°C/5 = 32

14*°C/5 = 32

°C = 32*5/14 = 80/7

Therefore °F = -80/7

a/q,

°F = -°C

now,

°C = -9*°C/5 + 32

°C+9*°C/5 = 32

14*°C/5 = 32

°C = 32*5/14 = 80/7

Therefore °F = -80/7

°F = (°C * 9/5) + 32

°C = (°F - 32) * 5/9To find the temperature when both are equal, we use an old algebra trick and just set ºF = ºC and solve one of the equations.°C = (°C * 9/5) + 32

°C - (°C * 9/5) = 32

-4/5 * °C = 32

°C = -32 * 5/4

°C = -40°F = (°F * 9/5) + 32

°F - (°F * 9/5) = 32

-4/5 * °F = 32

°F = -32 * 5/4

°F = -40

°C = (°F - 32) * 5/9To find the temperature when both are equal, we use an old algebra trick and just set ºF = ºC and solve one of the equations.°C = (°C * 9/5) + 32

°C - (°C * 9/5) = 32

-4/5 * °C = 32

°C = -32 * 5/4

°C = -40°F = (°F * 9/5) + 32

°F - (°F * 9/5) = 32

-4/5 * °F = 32

°F = -32 * 5/4

°F = -40