Answers

2015-08-07T19:55:00+05:30

This Is a Certified Answer

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Sin^2A/cos^2A  +  cos^2A/sin^2A
on taking lcm
sin^4A + cos^4A
   sin²A cos²A
(sin²A + cos²A)² - 2sin²Acos²A              (sin²A+cos²A=1)
        sin²Acos²A
⇒  1 - 2sin²Acos²A                              (1/sinA = cosecA  ,1/cosA=secA)
       sin²Acos²A
cosec²Asec²A - 2  = RHS
Hence proved
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2015-08-07T19:59:28+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Sin^2A/cos^2A  +  cos^2A/sin^2A
on taking lcm
sin^4A + cos^4A
   sin²A cos²A
⇒ (sin²A + cos²A)² - 2sin²Acos²A             
        sin²Acos²A
⇒  1 - 2sin²Acos²A                             
       sin²Acos²A
cosec²Asec²A - 2  = RHS
Hence proved
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