# 1 mole of Co2 gas is mixed with 1 mole of So2 gas find gama for the mixture?urgenttttt pleaseeeeee

1
by crmail

2015-08-20T07:24:42+05:30

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CO2 :  n1 = 1 mole     M1 = molar mass = 44 gm/mole      mass m1 = 44 gm
SO2 :  n2 = 1 mole     M2 = 64 gm/mole                 mass m2 = 64 gm

total mass of mixture = m = m1 + m2 = 108 gm
mole fractions    nf1 = 1/2    and  nf2 = 1/2
mass fractions:  mf1 = 44/108 = 11/27            mf2 = 64/108 = 16/27
molar mass of the mixture = M = nf1 * M1 + nf2 * M2
Mm  = 1/2 * 44 + 1/2 * 64 = 54 gm/Mole

Specific heats at constant pressure Cp:  (to find from some tables or use formulas)
Cp1 : of CO2: 0.839 J/gm-K          Cp2 of SO2 :  0.644 J/gm-K

Cp for the mixture = mf1 * Cp1 + mf2 * Cp2
Cpm = 11/27 * 0.844 + 16/27 * 0.644 = 0.7255 J/gm-K

average gas constant Rm for the mixture = R / Mm
Rm = (8.314 J/mol-K) / 54  J/gm-K = 0.1539 J/gm-K

Cv for the mixture Cvm = Cpm - Cvm = 0.5716 J/gm-K

Ratio of specific heats of mixture = γ_m = Cpm / Cvm = 1.2692 or 1.27 nearly

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Ratio of specific heats for CO2 = γ = 1.289
SO2 = γ = 1.29
Ratio of specific heats for the mixture is nearly same as that of the individual gases..because their specific  heats at constant pressure Cp values are close.

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