# 80 grams of NaOH is dissolved in 500 gram of water.calculate 1)molality of the solution and 2)mole fraction of NaOH in the solution. (atomic mass H=1,O=16,Na=23)

2
by Raksha1

2015-08-17T18:38:15+05:30
Molality = (weight/gram molecular weight)×(1/kg)
=(80 g/40 g/mol)×(1/.500 kg)
= 1.0 mol/kg
hence the molality of the solution is 1.0 mol/kg
2015-08-20T06:00:13+05:30

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Molarity is the concentration by volume of the solution. = moles/litre
Molality is the concentration by weight of the solvent = moles/kg.  This is an easier and convenient measure, as it is easier to measure the weight than volume.

moles of NaOH in 80 grams = 80/(24+1+16) = 2

Molality = moles of NaOH / weight of  the solvent in kg
= 2 / [ 500/1000  ]   = 4 moles/kg
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molar mass of water = 18
mole fraction of NaOH :
number of moles of NaOH in the solution = 80 grams/40 grams = 2
number of moles of water in 500 grams = 500/18 = 250/9

molar fraction =  2 /[ 250/9 + 2] = 9 /134

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