Answers

2014-01-29T11:23:11+05:30
Let the numbers be a and b. therefore a*b=192 and a-b=4. now we know the formula thatĀ (a-b)^2+4*a*b=(a+b)^2. henceĀ a+b= \sqrt{4*4+4*192}= \sqrt{4(4+192)}= \sqrt{4*196}=2*14=28
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2014-01-29T11:54:37+05:30
Let the larger number be x and smaller be y such that xy=192 and x-y=4 then,
(x+y)^2= {x^2+y^2+2xy} \\(x+y)^2=(x-y)^2+4xy \\(x+y)^2=16+768 \\(x+y)^2=784 \\x+y= \sqrt{784} \\(x+y)=28
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