Answers

  • Brainly User
2015-08-18T14:11:21+05:30
3x²-3√3x+2=0
a=3  b =-3√3  c = 2
use quadratic formula 
-b+-√b²-4ac/2a
put the values 
3√3+,-√(3√3)² - 4×2×3/2×3
3√3+-√27-24/6
3√3+-√3/6
x=(3√3+√3)6  and  x= (3√3-√3)6
x=√3(3+1)/6=√3 ×2/3=2/√3  and x = √3(3-1)/6=√3/3=1/√3
so the roots of this equation are2/√3 and 1/√3
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