A particle is moving in a circular path with constant speed v .What is the change in speed when the particle completes one-forth of revolution?

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there will be no change in speed as it is moving with constant speed
no answer is given square root of 2*v why this is i cant understand

Answers

2014-06-08T15:58:38+05:30
2014-06-08T16:15:35+05:30
THE SPEED REMAINS THE SAME AS IT IS CONSTANT
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