# An elevator descends into a mine shaft at the rate of 10 metres per min if it descends starts from 12m above the ground level how long will it take to reach -500mtrs

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by zachrayjohn

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by zachrayjohn

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500+12=512 is total distance

since +12 to 0 is 12 and 0 to -500 is 500.

speed=10m/minute

10/1=512/___

10/1=512/51.2

51.2 minute is the ans.

**Ans:51.2 minutes or 51minutes 12seconds**

since +12 to 0 is 12 and 0 to -500 is 500.

speed=10m/minute

10/1=512/___

10/1=512/51.2

51.2 minute is the ans.

The Brainliest Answer!

ending point = -500 m

total distance = 12 - (-500) = 12 + 500= 512m

speed = 10 meter per minute

time = distance / speed

= 512 / 10

= 51.2 minute

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