Answers

2014-01-30T17:23:47+05:30
Total distance travelled =x
then when the train is travelling with the velocity,v=40
=>x/t=40_____eq.(1)
and when the tym has been delayed 15 min.,then the  velocity will be,
x/t+15=35____eq.(2)
=>x=35(t+15)
=>x=35t+525
=>40t=35t+525[frm eq.1]
=>t=105
sub.t in eq.1,
x=4200.
require distance=4200km
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2014-01-31T11:50:07+05:30
Just say that it takes time="t" hrs  to reach its destination while moving at an avg speed of 40kmph. therefore distance= 40t. now, 15 min = 1/4 hr. therefore you get distance= 35(t+1/4) = 35t + 35/4. hence 40t = 35t+35/4 => 5t = 35/4 => t = 7/4 hrs. so distance = 40t = 40*7/4 = 70 km.
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