Answers

2015-08-28T17:37:09+05:30
2015-08-28T19:18:00+05:30
X² + x + 1 = 0 
Here , a = 1 , b = 1 , c = 1 
So , (-b+√b²-4ac)/2a , (-b-√b²-4ac)/2a are the roots of the given equation .
⇒(-1+√(1²)-4×1×1)/2×1 , (-1-√(1²)-4×1×1)/2×1 
⇒(-1+√1-4)/2 , (-1-√1-4)/2
⇒(-1+√-3)/2 , (-1-√-3)/2
⇒(-1+i√3)/2 , (-1-i√3)/2 
Therefore , (-1+1√3)/2 , (-1-i√3)/2 are the roots of the given equation .
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