Answers

2015-09-23T23:22:57+05:30

LET ABC BE TRIANGLE WITH MEDIANS AD,BE AND CF

THE SUM OF TWO SIDES OF A TRIANGLE IS MORE THAN TWICE THE MEDIAN BISECTING THIRD SIDE.

LET AD BE THE MEDIAN TO BC,BE TO AC AND CF TO AB,

THEN AB+AC>2AD--------1

BC+AB>2BE-----------------2

AC+BC>2CF------------------3

ADDING 1,2,3

2(AB+BC+AC)>2(AD+BE+CF)

AB+BC+AC>AD+BE+CF


REMEMBER ALWAYS TO WRITE IN FORMAT FOR PROVING A PROBLEM


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