# A bus starts from rest.if the acceleration is 0.5m/s what will be the velocity at the end of 2 min and what distance will cover during that time.

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Initial Velocity=0

Acceleration=0.5 m/s

Time=2 min or 120 Seconds

According to the equation of motion

v=u+at

v=0+0.5*120

v=0+60

v=60

Therefore, Final Velocity or velocity at the end of 2 min is 60.

According to the Equation of Motion

s=ut+1/2atsquare

s=0*120+1/2 * 0.5*14400

s=0+0.5*7200

s=3600

Therefore distance travelled is 3600 m

Acceleration=0.5 m/s

Time=2 min or 120 Seconds

According to the equation of motion

v=u+at

v=0+0.5*120

v=0+60

v=60

Therefore, Final Velocity or velocity at the end of 2 min is 60.

According to the Equation of Motion

s=ut+1/2atsquare

s=0*120+1/2 * 0.5*14400

s=0+0.5*7200

s=3600

Therefore distance travelled is 3600 m