# The length of rectangular field is three more than twice it's breath. If the perimeter of the field is 228m find the dimensions of field

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by kashu1

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by kashu1

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breadth = y

x= 2y+3

perimeter = 2(l+b)

so x+y = 228

x=2y+3

x+y+228 by substitution method we get

2y+3+y= 228

3y+3=228

3y=228-3

3y = 225

y= 225/3

y = 75

x+y =228

x+75+= 228

x= 228-75

x=153

so length =135 and breadth =75

Let the breadth be = x,

then length = 3 more than twice the breadth = 2x +3.

The perimeter of any rectangle = 2(l + b),

But it is given that the perimeter = 228m.

therefore, 2(l+b) = 228

⇒2[(2x +3) + (x)] = 228

⇒2(2x+3)+ 2(x) = 228

⇒4x + 6 + 2x = 228

⇒6x + 6 = 228

⇒6x = 228 - 6

⇒6x = 222

⇒x = 222/6 ⇒37.

therefore x=37m.

then breadth = x= 37m,

length = 2x +3 =2(37) +3 ⇒ 74 + 3 = 77m.

therefore length = 77m and breadth = 37m