Answers

  • Brainly User
2015-09-11T18:58:41+05:30
Let length = x
breadth = y

x= 2y+3
perimeter = 2(l+b)
so  x+y = 228

x=2y+3
x+y+228  by substitution method we get

2y+3+y= 228
3y+3=228
3y=228-3
3y = 225 
y= 225/3
y = 75

x+y =228
x+75+= 228
x= 228-75
x=153

so length =135  and breadth =75
0
when we find the perimeter of the rectangle with your dimensions the perimeter is 420 but the perimeter is given as 228m
2015-09-11T19:25:01+05:30
In the rectangular field,
Let the breadth be = x,
then length = 3 more than twice the breadth = 2x +3.
The perimeter of any rectangle = 2(l + b),
But it is given that the perimeter = 228m.
therefore, 2(l+b) = 228
⇒2[(2x +3) + (x)] = 228
⇒2(2x+3)+ 2(x) = 228
⇒4x + 6 + 2x = 228
⇒6x + 6 = 228
⇒6x = 228 - 6
⇒6x = 222
⇒x = 222/6 ⇒37.
therefore x=37m.
then breadth = x= 37m,
length = 2x +3 =2(37) +3 ⇒ 74 + 3 = 77m.
therefore length = 77m and breadth = 37m
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