Answers

2014-06-16T00:01:07+05:30
LET THE ROOTS OF EQUATION BE α
on comparing given equation with Ax²+Bx+C=o
A=(b-c), B=(c-a), C=(a-b)
now sum of roots=-B/A
                   α+α=-(c-a)/(b-c)
                      2α=a-c/(b-c)......1
product of roots=C/A
                    α²=(a-b)/(b-c)
putting the value of α from 1
   \frac{ (a-c)^{2} }{4 (b-c)^{2} } = \frac{a-b}{b-c}
on solving we get 2b=a+c
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