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## Answers

⇒[(x)² + (-3) - 2(x)(-3)]

⇒[x² + 9 - 2x(-3)] - 4

⇒[x² + 9 -6x] - 4

⇒x² - 6x + 9 - 4

⇒x² - 6x + 5

⇒x² - 5x - x + 5

⇒x(x - 5) - 1(x - 5)

⇒(x - 5)(x - 1).

If you want further x values can be found as x= 5 or 1

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⇒[(x)² + (-3) - 2(x)(-3)]

⇒[x² + 9 - 2x(-3)] - 4

⇒[x² + 9 -6x] - 4

⇒x² - 6x + 9 - 4

⇒x² - 6x + 5

⇒x² - 5x - x + 5

⇒x(x - 5) - 1(x - 5)

⇒(x - 5)(x - 1).

If you want further x values can be found as x= 5 or 1