# Limits x tends to infinite under root x square + x -under root x. plss urgent ..

2
by sameer5
Lim √x2 + x - √x
x->∞
aisa??
Lim √x2 + x - √x
yes
okk

2015-09-14T18:39:25+05:30

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Lim √x2 + x - √x
x->∞
let x=1/y so that y->0, when x->

Lim √1/y2 + 1/y - √1/y
y->0
Lim 1/y + 1/y - √1/y
y->0
Lim (1+1)/y - √1/y
y->0
Lim 2/y - √1/y
y->0
Lim 2/y - 1/√y
y->0
Lim (2√y - y)/y√y
y->0
Lim (2√y - y)/y√y x (2√y + y)/(2√y + y)
y->0
Lim (4y - y2)/y√y(2√y + y)
y->0
Lim (4y - y2)/(2y2 + y2√y)
y->0
dividing each term with the highest power of y
Lim (4y/y2 - y2/y2)/(2y2/y2 + y2√y/y2)
y->0
Lim (4/y - 1)/(2 + √y)
y->0
(4/0 - 1)/(2 + 0)
0 - 1 / 2
4/y -> infinity and not 0...
no no
oops haa
yes ri8
thanks
2015-09-15T02:38:08+05:30

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The given question is not clearly specified.

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*under root x2+x
and + x will be out of under root
use parentheses ( ) , [ ] { } brackets to clearly write the expression please
Lim √x2 + x - √x
x->∞
this is the question