Answers

2015-09-14T23:23:53+05:30
Let a line segment PQ have mid pts. X and Y....
so,PX=QX.....(1)
PY=QY....(2)
since,P,Q,X n Y are collinear,
PX+QX=PQ and PY+QY=PQ
So,PX+QX=PY+QY
or,2PX=2PY
or,PX=PY....(3)
now,statement (3) is a contradiction until X and Y coincide
Hence,it can be concluded,that a line segment can have only 1 mid-pt.

0