# A boy on a cliff 19.6m high drops a stone. one second later, he throws a second stone after the first. they hit the ground at the same time. with what speed did he throw the second stone

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by chinukarthik

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by chinukarthik

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Let T be the time taken by the 1st stone to travel 19.6 m.

s = u t + 1/2 a t² for the 1st stone

19.6 = 1/2 * g * T²

T = √(39.2/ 9.8) = 2 sec

2nd stone:

19.6 = u * 1sec + 1/2 g 1²

u = 14.7 m/sec

This is the speed with which the second stone is thrown.

s = u t + 1/2 a t² for the 1st stone

19.6 = 1/2 * g * T²

T = √(39.2/ 9.8) = 2 sec

2nd stone:

19.6 = u * 1sec + 1/2 g 1²

u = 14.7 m/sec

This is the speed with which the second stone is thrown.