# In figure, Angle ACB is right angle & AC=CD & CDEF is Parallelogram .If Angle FEC=10,then Calculate angle BDE...

2
by nesthangam

2015-09-15T13:35:50+05:30
Now triangle ACB is a right triangle.
so,∠acb =90°
as AC II DE, ∠BDE=90°.
As CDEF is a parallelogram,
∠f=∠d.
THUS,∠ACD=∠BDE

2015-09-15T17:22:24+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Angle ECD = angle FEC = 10°  as CD and EF are parallel.
angle DCA = angle BCA - angle ECD = 90 -10° = 80°

in triangle ACD, AC = CE  . so it is an isosceles triangle.
so angle CAD = angle ADC  = (180 - angle DCA)/2 = 50°

in triangle DCE, angle CDE = 180 - angle DCE - angle DEC =
= 180 - 10 - 90 = 80°

Hence  at point D on AB,
angle BDE = 180 - angle ADC - angle CDE = 180 - 50 - 80 = 50°

click on thanks button above please