# Given A=i^+3j^ & B=i^+j^.find the component of vector A along B.also find the component of vector A along B

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Vector A = i + 3 j magnitude = √(1+9) = √10

vector B = i + j magnitude = √2

angle between them = Ф

Cos Ф=*A . B* / (√10 * √2) = (1*1+3*1) / (√20) = 2/√5

Component of vector A along B is A cosФ = (i + 3 j) * 2/√5

component of vector B along A is B cos Ф = (i + j) 2/√5

vector B = i + j magnitude = √2

angle between them = Ф

Cos Ф=

Component of vector A along B is A cosФ = (i + 3 j) * 2/√5

component of vector B along A is B cos Ф = (i + j) 2/√5