When an AC source of emf e=E sin(100t) is connected across a circuit, phase difference between the emf e and current I in the circuit is observed to be π/4.If the circuit consists of possibly R_L or R_C or L_C in series find the relationship between two elements.

1

Answers

2015-09-16T04:08:17+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
   e = E Sin 100 t    =>  ω = 100 rad/sec

1)  R L circuit:

    Z = √ [R² + XL² ]
   I = (E /Z)  Sin (ω t + Ф)        where    tan Ф = - XL / R      So Ф is negative.
           So  XL = R  as     Ф = π/4
                 R = ω L = 100 L

2) RC  circuit
     i = (E / Z)  Sin (ω t + Ф)       where  Z  = √ [R² + Xc²]
          tan Ф = Xc / R = 1/(RωC)  = tan π/4 = 1              
         So  R = 1/(ωC)

3)
LC  case:
       Here  the phase difference between the current and the voltage is 90 deg.  It is leading or trailing depends on the values o f  XL  and Xc.  Which ever is more or less.

1 5 1