Answers

2015-10-20T15:01:30+05:30
given,
acceleration due to gravity=9.8m/s^2
initial velocity=0m/s^2
distance =4.9m
therefore,
time taken,
s=ut+1/2at^2
4.9=0*t+1/2*9.8*t^2
4.9=4.9*t^2
4.9/4.9=t^2
1=t
therefore time taken=1sec.
1) s=ut+1/2at^2
    4.9=0*2+1/2*a*(2)^2
    4.9=2a
    2.45=a
therefore acceleration in time 2sec=2.45m/s^2
2) s=ut+1/2at^2
    4.9=0*1+1/2*a(1)^2
    4.9=1/2a
    4.9*2=a
    9.8=a
therefore acceleration in time 1sec=9.8m/s^2.
        i hope that this will help u.................
1 1 1