# The weight of the body on the surface of earth is 392N what will be the weight of this body in another body whose mass is double of earth mass and radius is fourth multiple of earth radius?

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by asfhjkloy

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by asfhjkloy

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Let the mass of the body on the surface of Earth = m kg

weight of the body on Earth = m * g = G M m / R²

g = 9.8 m/sec² on Earth

g = acceleration due to gravity = G M / R²

The weight of a body on a planet is directly proportional to Mass of the planet and inversely proportional to square of radius of the planet.

weight = 392 * 2 / (4)² Newtons = 98 Newtons

weight of the body on Earth = m * g = G M m / R²

g = 9.8 m/sec² on Earth

g = acceleration due to gravity = G M / R²

The weight of a body on a planet is directly proportional to Mass of the planet and inversely proportional to square of radius of the planet.

weight = 392 * 2 / (4)² Newtons = 98 Newtons