# How many kg of steam at 110 degree celsius is needed to have 10 kg of ice at 0 degree celsius converted to water at 30 degree celsius?

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by TanehaPatel

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by TanehaPatel

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Let s1 = specific heat of steam. in Joules/kg

m1 = mass of steam in kg

s2 = specific heat of water in Joules/kg

L1 = latent heat of steam per kg

L2 = latent heat of fusion. per kg

heat given by steam when its temperature comes from 110 to 30 deg.C

= heat absorbed by ice and converted water to rise to 30 deg C.

s1 * (110 C - 100 C) * m1 + L1 * m1 + s2 * (100 C - 30 C) * m1

= 10 kg * L2 + 10 kg * s2 (30 C - 0 C)

Substituting the other known values, you should the value of m1.

m1 = mass of steam in kg

s2 = specific heat of water in Joules/kg

L1 = latent heat of steam per kg

L2 = latent heat of fusion. per kg

heat given by steam when its temperature comes from 110 to 30 deg.C

= heat absorbed by ice and converted water to rise to 30 deg C.

s1 * (110 C - 100 C) * m1 + L1 * m1 + s2 * (100 C - 30 C) * m1

= 10 kg * L2 + 10 kg * s2 (30 C - 0 C)

Substituting the other known values, you should the value of m1.