2015-09-18T20:07:09+05:30

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Max h=(v₀)²sin²(q) /2 g

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MASelvam IITian
Booksworm.
2015-09-18T20:27:47+05:30

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
U = initial velocity of the projectile
θ = angle of projection with the horizontal
H = maximum height above the horizon that the projectile attains
= u² Sin²θ / (2 g)

derivation:
initial velocity in vertical direction = u sinθ
v² = u²  - 2 g H
v = 0  when the projectile reaches the top.
distance travelled  H = u² Sin² θ / 2 g

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