# What is the ratio in the change of momentum if the mass is doubled,mass is halved,mass and velocity incresases by 3 times.....

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We are dealing with magnitudes of quantities.

Linear Momentum = mass * velocity

initial momentum = m * v = p (let)

Change in momentum = m2 * v2 - m * v

1) mass m2 = 2 * m velocity = v

change = 2 m v - m v = m v = p = initial momentum.

2) mass is halved . m2 = m/2

change = m/2 * v - m v = - m v /2 = half of initial momentum

3) m2 = 3 m v2 = 3 v

change = m2 v2 - m v = 9 m v - m v = 8 m v

is 8 * initial momentum

Linear Momentum = mass * velocity

initial momentum = m * v = p (let)

Change in momentum = m2 * v2 - m * v

1) mass m2 = 2 * m velocity = v

change = 2 m v - m v = m v = p = initial momentum.

2) mass is halved . m2 = m/2

change = m/2 * v - m v = - m v /2 = half of initial momentum

3) m2 = 3 m v2 = 3 v

change = m2 v2 - m v = 9 m v - m v = 8 m v

is 8 * initial momentum

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