This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
We are dealing with magnitudes of quantities.
Linear Momentum =  mass * velocity
         initial momentum  = m * v = p  (let)

Change in momentum = m2 * v2  -  m * v

1) mass m2 = 2 * m        velocity = v
                change = 2 m v -  m v = m v = p = initial momentum.

2)  mass is halved .   m2 = m/2
           change = m/2 * v  - m v  = - m v /2  = half of initial momentum

3)  m2 = 3 m       v2 = 3 v
         change =  m2 v2 - m v  =  9 m v - m v = 8 m v
                 is 8 * initial momentum

1 5 1
click on thanks button above please
select best answer pls
but i need the answers in the ratio form.pls read the question properly
The Brainliest Answer!
Let p¹ be d initial momentum and p² be momentum after change in every case 1case P¹= m*v But if mass is doubled then, P²= 2(m)*v P² is directly proportional to m, therefore the 2p¹=p² Hence ratio=2:1 Similarly, 2case Mass is halved the momentum will also bcome half Hence, ratio=1:½ Similarly, Case 3 P¹=m*v P²~3m*3v P²=9mv Hence ratio=9:1
2 5 2
Hope dis helps, mark as besr brainliest answer plzz....and press thanks button
thank u so much