# The angles of an triangle are (x-40) , (x-20) and (x/2 - 10) . find the value of x and then the angles of an triangle.

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by gaurav6

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by gaurav6

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the angles are (x-40) , (x-20) and (x/2 - 10).

Sum = (x-40) + (x-20) + (x/2 - 10) = 180

⇒ 5x/2 - 70 = 180

⇒ 5x/2 = 180+70 = 250

⇒ x = 250×2/5

⇒ x = 100

Angles are:

x-40 = 100 - 40 = 60

x - 20 = 100 - 20 = 80

x/2 - 10 = 100/2 - 10 = 40

x-40+x-20+x/2-10=180(angle sum property

2x+x/2-70=180

5x/2=180+70

5x=250into2

5x=500

x=100

therefore angles are

60,80&40