# Show that the following points taken in order form the vertices of a rhombus.( - 4, - 7), ( - 1, 2), (8, 5) and (5, - 4)

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XY= √(x2- x1)² + (y2- y1)² )

AB=√ ((-1-(-4))²+ (2-(-7))²

= √(3²+ 9²)

=√(90)

BC= √(8-(-1))²+ (5-2)²

= √9²+3²

CD= √(5-8)²+ (-4-5)²

AD= √(5-(-4))²+(-4-(-7))²

∴

AC=√(8-(-4))²+ (5-(-7))²

=√144+144

BD=√(5-(-1))²+(-4-2)²

= √36+36

∴