Answers

2015-09-25T16:49:21+05:30
R = 6.4×10³ km = 6.4×10⁶ m
g = 9.8 m/s²

Escape velocity, V_e =  \sqrt{ \frac{2GM}{R} }

V_e = \sqrt{ \frac{2GM}{R} } =\sqrt{2 \times  \frac{GM}{R^2} \times R } =\sqrt{2 \times g \times R  } \\ \\ \Rightarrow V_e= \sqrt{2 \times 9.8 \times 6.4 \times 10^6} =11.2 \times 10^3\ m/s\\ \\ \Rightarrow V_e=11.2\ km/s

So the body should be projected at 11.2 km/s
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