# An artificial satellite revolves around the Earth at a distance of 3400 km. Calculate its orbital velocity and period of revolution. Radius of the Earth = 6400 km; g = 9.8 m/s²

2
by Ishi262

2015-09-25T15:04:25+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
v = orbital velocity        we know  g = G M / R²
d  = 3400 + 6400 km = 10000 km

gravitational force = centripetal force
G M m / d²  =  m v² / d
v² = G M / d  = g R² / d
v = R √(g/d)

ω = angular velocity =  v / R = √(g/d)
T = time period = 2π/ ω  = 2 π √(g/d)

substitute the values to get answers.
2015-09-28T22:37:45+05:30
Distance of artificial satellite (d)= 3400 km
Radius of earth(R) = 6400 km = 6.4×10⁶ m
Radius of orbit(r) = R+d = 10,000 km = 10⁷ m
g = 9.8 m/s²
Orbital velocity,
Period of revolution, T = ?

(i) Orbital velocity

(ii) Time period