# An orbital satillite revolves around the earth at a distance of 3400km calculate its orbital velocity and period of revolution. radius of earth is 6400km g is 9.8 ms-1

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by swathitha

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by swathitha

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Radius of earth(R) = 6400 km = 6.4×10⁶ m

Radius of orbit(r) = R+d = 10,000 km = 10⁷ m

g = 9.8 m/s²

Orbital velocity,

Period of revolution, T = ?

(i) Orbital velocity

(ii) Time period