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Please solve fast

You are given a and b are rational numbers. If (3-√2)/3+√2=a + b√2, then find the value of a and b

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You are given a and b are rational numbers. If (3-√2)/3+√2=a + b√2, then find the value of a and b

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The Brainliest Answer!

solving

3-√2/3+√2=3-√2/3+√2 *3-√2/3-√2 in this step we have rationalised by 3-√2

this will give you (3-√2)²/9-2 using (a+b)(a-b)=a²-b²

=9+2-6√2/7

=11=6√2/7

=a=11/7

b=6/7 by comparing a+b√2 by our ans

sorry it was my mistake it is -6/7 as while comparing a+b√2=11+(-6√2)/7

once again sorry! so b=-6/7