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Q_1=2 \times 10^{-7}C\\Q_2=3 \times 10^{-7}C\\R=30cm=0.3m\\ \\F= \frac{1}{4 \pi \epsilon_o}\  \frac{Q_1Q_2}{R^2}=9 \times 10^9 \times \frac{2 \times 10^{-7} \times 3 \times 10^{-7}}{0.3^2} =\boxed{0.006N}

Force acting between the charges is 0.006N and it is repulsive(since it is positive)