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In a certain a.p the 24th term is twice the 10th term . Prove that the 72nd term is twice the 34th term?

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by sandy661

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by sandy661

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Using fomula of n th term = a + (n - 1)d

given a + (24 - 1)d = 2(a + (9 - 1)d)

solving the equation we get a = 5d

again taking

a + (24 - 1)d = 2(a + (9 - 1)d)

⇒3a + (72 - 3)d = 6a +54d

⇒(a + (72 - 1)d) + 2 (a - d) = 6a + 54d

⇒(a + (72 - 1)d) = 2a + 10d + 56d

⇒a + (72 - 1)d) = 2(a + (34 - 1)d)

hence proved 72nd term is twice the 34th term.

i am done minor step jumps if you have any problem comment under the answer.

given a + (24 - 1)d = 2(a + (9 - 1)d)

solving the equation we get a = 5d

again taking

a + (24 - 1)d = 2(a + (9 - 1)d)

⇒3a + (72 - 3)d = 6a +54d

⇒(a + (72 - 1)d) + 2 (a - d) = 6a + 54d

⇒(a + (72 - 1)d) = 2a + 10d + 56d

⇒a + (72 - 1)d) = 2(a + (34 - 1)d)

hence proved 72nd term is twice the 34th term.

i am done minor step jumps if you have any problem comment under the answer.