If one zero of the polynomial 3x2 - 8x 2k 1 is seven times of other then find the value of k

1

2015-10-01T11:35:33+05:30
The polynomial equation is in the form of
Where a and 7a are the two roots.
So let the given equation be:
+ \frac{1}{3} [/tex]

Comparing both:
Sum of zeroes:
a+7a=
8a =
a = 1/3

Product of zeroes:
(a)(7a)= + \frac{1}{3} [/tex]
()() =
= 2k+1
7 = 3(2k+1)
7 = 6k+3
6k = 4
k =