# The adjacent sides of a parallelogram ABCD measure 34 cm and 20 cm, and the diagonal AC measures 42 cm. Find the area of the parallelogram.

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by Mittutti

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by Mittutti

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Area of the parallelogram=sum of the area of the two triangles, made by any one of the diagonal, right!!!

Area of a triangle=1/2*base*height

Here, we know all the three sides- 34,20,42.

So, we have to use the Heron's formula.

s=semi-perimeter=34+20+42/2

=96/2

=48 cm.

Let a=34, b=20; and, c=42.

**Area of a triangle, =**√s(s-a)(s-b)(s-c)

**=**√48(48- 34)(48-20)(48-42) It is because s=48, a=34, b=20, c=42.

**=**√48*14*28*6

**=**√112896

=336 cm².

Therefore, are of the parallelogram= 2*336

=672 cm².

Thank you.

Hope this will help you.

Area of a triangle=1/2*base*height

Here, we know all the three sides- 34,20,42.

So, we have to use the Heron's formula.

s=semi-perimeter=34+20+42/2

=96/2

=48 cm.

Let a=34, b=20; and, c=42.

=336 cm².

Therefore, are of the parallelogram= 2*336

=672 cm².

Thank you.

Hope this will help you.