# The acceleration a=F/m where F=100+-(it is plus or minus)5 and m=(10+-0.2) kg.find the %error in a

1
by Raksha1

2015-10-05T15:28:39+05:30

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acceleration = a = F / m    =>  F = m * a

Let us say in measurements of acceleration and mass the errors are Δa and Δm respectively.  The errors come in because of the minimum count of measuring instruments like a scale (least count of 1 mm).  Let the resulting error in Force that is calculated be ΔF.

F + ΔF = (m +Δm) (a + Δa)
= m a + a Δm + m Δa + Δm Δa
Δm Δa is usually very very small as compared to other quantities on RHS.  We take absolute values of Δm and Δa, as we are interested in the maximum error on the positive or negative side.

=> ΔF = a  Δm  + m Δa
=>  ΔF/F =  Δm / m  +  Δa  / a
=>  ΔF/F  * 100  =  Δm / * 100  + Δa / a * 100

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a = F / m

Δa / a  * 100  =  ΔF / F * 100  +  Δm/m * 100
% error in a = % error in F + % error in m

ΔF = 5 units        Δm = 0.2 units

%error in a = 5/100 * 100 + 0.2 /10  * 100
= 7

Force a = F / m  = 100 / 10  =  10 m/sec²    This is what is measured and calculated using the instruments and equipment we have.
While reporting this value of a , we say that it is :
a   =  10 +- 7%  m/sec²  ,    or      a  =  10 +- 0.7  m/sec²

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OR,  relative error in a
=  relative error in measurement of F  +  relative error in  measurement of m

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