# I have a box. The top's area is 240 square inches, the front's area is 300 square inches and the end's area is 180 square inches. What are the dimensions of the box?

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by prasrosmit

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by prasrosmit

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This is easily solved with a little simple algebra. If we call the three sides A, B, and C we have:

A x B = 240

A x C = 300

B x C = 180

Multiplying these together we get:

(A x B) x (A x C) x (B x C) = 240 x 300 x 180

A2 x B2 x C2 = 12,960,000

(A x B x C)2 = 12,960,000

Which means that:

A x B x C = 3600

Substituting A x B = 240 back in gives C = 15 and the rest follow.