# A student recorded the weight of dry raisins as 5.4g and on soaking them for 4-5 hrs the weight was 7.6g.calculate the percentage of water imbibed by the raisins

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by srijaguduri

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by srijaguduri

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Dry weight of raisins = 5.4g

weight weight of raisins = 7.6g

weight of water imbibed,

% of water imbibed =

**Hence, Percentage of water imbibed is 40.74%**

weight weight of raisins = 7.6g

weight of water imbibed,

% of water imbibed =

weight of raisins after soaking them=7.6g

% of water imbided by raisins=(weight of wet raisins-weight of dry raisins÷weight of dry raisins)×100