Answers

2014-06-21T17:44:17+05:30
(x+2)/{(x+1)(x²+1)} = A / (x+1) + (Bx+C)/{x²+1}
                           = (Ax²+1+Bx²+Bx+Cx+C)/{(x+1)(x²+1)}
        on comparing the coefficient of both side of same power

A+B = 0
B+C = 1
A+C = 2
A =1/2 ; B =-1/2 ; C= 3/2
put the value of A,B,C
     = 1/2{1/(x+1) + (3-x)/(x²+1)} 
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