Answers

2014-06-21T20:01:31+05:30
For number to be divisible by 4 last two digit must be divisible by 4
let five position are  _  _  _  _  _  
if we put 2 at the ones then we can put 1,3,5 at tens position and remaining three place can be done by 3! ways .
if we put 4 at ones then we put 2  at tens and remaining 3 can be done by 3! ways 
so total number of ways = 3*3! + 3! = 24
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